一道很简单的C语言题目 11行代码求解。谢谢。谢谢；

你的补充代码是正确的啊，没有错误，我运行过了，一切正常。。。。。我注意到第一段代码的
scanf("%d%d ",a,b);里在第二个%d后边多了一个空格，而补充代码里没有，不知道是不是笔误，当然是不应该有这个空格的。另外，建议在打印语句printf("%d%d",a,b);里加上空格和换行printf("%d %d
",a,b);(你的代码是porint，应该是笔误。。。)

#include #include #include "string.h"int main(int argc, char *argv[]) {char s[50];int i,len;float sum=0;while(1){sum=0.0;printf("
请输入：");fflush(stdin);scanf("%s",s);len=strlen(s);for(i=0;i='A' && s[i]='A' && s[i+1]='0' && s[i+1]<='9'){sum+=(s[i+1]-48)*temp;}}}printf("
分子量为：%.3f",sum);printf("

继续？[y/n]: ");char c;fflush(stdin) ;scanf("%c",&c);if(c!='y' && c!='Y'){break;}}return 0;}

Library ieee;
Use ieee.std_logic_1164.all;
Use ieee.std_logic_arith.all;
Use ieee.std_logic_unsigned.all;
Entity watch is
Port(sel: out std_logic_vector(6 downto 1) ;
seg:out std_logic_vector(7 downto 0);
Beginstop:in std_logic;
Reset:in std_logic;
Cp2:in std_logic);
End watch;
Architecture behave of watch is
Signal num1: std_logic_vector(3 downto 0);
Signal num2: std_logic_vector(3 downto 0);
Signal num3: std_logic_vector(3 downto 0);
Signal num4: std_logic_vector(3 downto 0);
Signal num5: std_logic_vector(3 downto 0);
Signal num6: std_logic_vector(3 downto 0);
Signal num: std_logic_vector(3 downto 0);
Signal numlet: std_logic_vector(2 downto 0);
Signal count: std_logic_vector(17 downto 1);
Signal selsig: std_logic_vector(6 downto 1);
Signal segsig: std_logic_vector(7 downto 0 );
Signal cp1: std_logic;
Signal cp3: std_logic;
Begin
Process(cp2) ---- 分频。
Begin
If (cp2' event and cp2='1') then
if (Count="1100011010011111")then
count<="00000000000000000"; cp1<=not cp1;
else count<=count+1;
end if;
end if;
cp3<=count(10);
end process;
process(cp1)
begin
if reset ='1' then num1(3 downto 0) <="0000";
num2(3 downto 0) <="0000";
num3(3 downto 0) <="0000";
num4(3 downto 0) <="0000";
num5(3 downto 0) <="0000";
num6(3 downto 0) <="0000";

else if cp1' event and cp1='1' then
if beginstop='1' then num1<=num1+1;
if num1 (3 downto 0)="1001" then
num1 (3 downto 0)<="0000"; num2<= num2+1;
if num2 (3 downto 0)="1001" then
num2 (3 downto 0)<="0000"; num3<= num3+1;
if num3 (3 downto 0)="1001" then
num3 (3 downto 0)<="0000"; num4<= num4+1;
if num4 (3 downto 0)="0101" then
num4 (3 downto 0)<="0000"; num5<= num5+1;
if num5 (3 downto 0)="1001" then
num5 (3 downto 0)<="0000"; num6<= num6+1;
if num6 (3 downto 0)="0101" then
num6(3 downto 0)<="0000";
end if; end if; end if; end if; end if; end if; end if;
end if; end if;
end process;
process (cp3)
begin
if (cp3' event and cp3='1')then
if(numlet(2 downto 0)="000") then
num<=num1;selsig(6 downto 1)<="111110"; end if;
if(numlet(2 downto 0)="001") then
num<=num2;selsig(6 downto 1)<="111101"; end if;
if(numlet(2 downto 0)="010") then
num<=num3;selsig(6 downto 1)<="111011"; end if;
if(numlet(2 downto 0)="011") then
num<=num4;selsig(6 downto 1)<="110111"; end if;
if(numlet(2 downto 0)="100") then
num<=num5;selsig(6 downto 1)<="101111"; end if;
numlet(2 downto 0)<=numlet(2 downto 0)+1;
if(numlet(2 downto 0)="101") then
numlet(2 downto 0)<="011111"; end if;
end if;
if (num (3 downto 0)="0000")then
segsig(7 downto 0)<="01111111"; end if;
if (num (3 downto 0)="0001")then
segsig(7 downto 0)<="00001101"; end if;
if (num (3 downto 0)="0010")then
segsig(7 downto 0)<="10110111"; end if;
if (num (3 downto 0)="0011")then
segsig(7 downto 0)<="10011111"; end if;
if (num (3 downto 0)="0100")then
segsig(7 downto 0)<="11001101"; end if;
if (num (3 downto 0)="0101")then
segsig(7 downto 0)<="11011011"; end if;
if (num (3 downto 0)="0110")then
segsig(7 downto 0)<="11111011"; end if;
if (num (3 downto 0)="0111")then
segsig(7 downto 0)<="00001111"; end if;
if (num (3 downto 0)="1000")then
segsig(7 downto 0)<="11111111"; end if;
if (num (3 downto 0)="1001")then
segsig(7 downto 0)<="11011111"; end if;
end process;
sel<=selsig;
seg(7 downto 0)<=segsig(7 downto 0);
end behave;

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